Hi!
----
Can anyone explain why the code below behaves differently (in
ast-ksh.2013-05-24 on SuSE 12.3/AMD64/64bit) when function "f" has an
own scope ? Are function-local variables not subject to be part of a
namespace ? What will happen to function-static variables vs.
namespaces ?
-- snip --
$ ksh -c 'f() { namespace nam1 { integer i2=5 ; } ; print ${.nam1.i2} ; } ; f'
5
$ ksh -c 'function f { namespace nam1 { integer i2=5 ; } ; print
${.nam1.i2} ; } ; f'
-- snip --
----
Bye,
Roland
--
__ . . __
(o.\ \/ /.o) [email protected]
\__\/\/__/ MPEG specialist, C&&JAVA&&Sun&&Unix programmer
/O /==\ O\ TEL +49 641 3992797
(;O/ \/ \O;)
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