Can you exclude any character from your input data to be used as a separator? Then you could redefine the read separator (in the example below I used X):
printf "\n\n\n\n\n" | IFS= read -dX FOO Date: Mon, 16 Dec 2013 21:02:01 +0000 From: [email protected] To: [email protected] Subject: [ast-users] Raw command substitution "$()" Hi guys,I'm looking for a method to do raw command substitution. The issue:- Need a ksh93t+ / ksh93u facillity to be able to take the literal output of a command with no substitutions or omissions, where the substitute data is less than 1kB. Target platforms are RHEL 6.4, Solaris 11 & AIX 7.1. Examples. printf is used below for illustration only.- $(), command substitution, i.e. FOO=$(printf "\n\n\n\n\n"); seems unsuitable as it modifies the output by performing some whitespace handling, such as stripping newlines. In this example, FOO returns zero-length.- "$()", quoted, prevents the field splitting and pathname expansions, but doesn't protect the trailing whitespace.- Binary read, i.e. printf "\n\n\n\n\n" | read -N$length FOO; works provided the $length of the read doesn't encounter the EOF, in this case values 1-5. If $length>5, in this example, FOO becomes zero-length. For an input of unknown length, this feels impractical.- One possible workaround is adding a suffix and then chopping it, i.e. FOO="$(printf "\n\n\n\n\nmysuffix")"; FOO="${FOO%mysuffix}" Any advice on the best way to acquire the literal command output? Thanks! -G _______________________________________________ ast-users mailing list [email protected] http://lists.research.att.com/mailman/listinfo/ast-users
_______________________________________________ ast-users mailing list [email protected] http://lists.research.att.com/mailman/listinfo/ast-users
