* chuli <[EMAIL PROTECTED]> [2007-12-25 09:42]:
> Hello, everyone
>
> When I use such script with ksh, it will produced "Segment fault!"
> But when I use it with bash, it will output normally. Why does ksh print
> "Segment fault"?
> for((;i<10;i++))
> do
> echo $i -----> or just use "$i" here
> done
> "
The man page says:
for (( [expr1] ; [expr2] ; [expr3] )) ;do list ;done
The arithmetic expression expr1 is evaluated first
So you need to initialize your i
(( i=0; i < 10, i++ ))
If you do:
while (( z < 10 ))
do
...
And you don't initialize your z you'll get the same thing!
ksh prints "Segment fault" or "Bus error" on Version M 1993-12-28 p on Mac OS X
because i is not initialized!
Jerry
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