Finnbarr Murphy schrieb:
$ tt='a\?b'
$ echo $tt
a\?b
$ echo `print $tt`
a\?b
$ echo $(echo $tt)
a\?b
$ echo $(eval print $tt)
a*b
$ echo $(eval echo $tt)
a*b
Note that '?' is being replaced by '*' when eval is involved.
Which version are you using? I get the correct output 'a?b' with the
latest version.
Regards,
Bernd
--
Bernd Eggink
[EMAIL PROTECTED]
http://sudrala.de
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