On Tue, May 13, 2008 at 01:18:40PM +0200, William James wrote:
> Imagine I have a file like this:
>
> buf="$(cat <<EOF
> part1: a part
> part5: another part
> # comment
> part9: 9th part
> EOF
> )"
>
> How can I get the line containing 'part5' using ksh93 string
> operators, avoiding both 'while read...' and 'sed'? I tried
> ${buf##pattern}, ${buf#pattern}, ${buf%pattern}, ${buf%%pattern} but
> they all _remove_ the string pattern. I need a string operator which
> only leaves the string matching pattern and removes the rest.
Not a string operator but this seems to work:
buf="$(cat <<EOF
part1: a part
part5: another part
# comment
part9: 9th part
EOF
)"
OIFS="$IFS"
IFS=$'\n'
lines=(${buf})
IFS="$OIFS"
typeset -i [EMAIL PROTECTED]
while let i-- ; do
case "${lines[$i]}" in
part5:*)
echo "${lines[$i]}"
break
;;
esac
done
on the other hand, a read loop within a pipe or simply a loop
with reading from stdin on the file seems much faster:
while read line ; do
case "$line" in
part5:*)
echo "$line"
break
;;
esac
done <<EOF
part1: a part
part5: another part
# comment
part9: 9th part
EOF
//Werner
--
"Having a smoking section in a restaurant is like having
a peeing section in a swimming pool." -- Edward Burr
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