Mario DeFazio wrote:
>
> I probably should know this, but is there a way to
> make a copy of array A to array B without writing a loop construct?
>
> I have tried initializing B[0]=
> and then doing
> B=${A}
> or
> B=${A[*])
>
> but I'm not getting the desired results.
> If each element of A is a single word, then
> set -A B ${A[*]}
>
> works, but that's rather limited.
>
> At the moment I just want to copy a simple numeric indexed array
> but I'd also like to know how to do an associative array, too.
Technically something like $ typeset -a ar=( "${arr...@]}" ) # works for
non-sparse indexed arrays but it does not make 1:1 copies nor does it
work for sparse indexed or associative arrays...
AFAIK one way which works reliable for all types of variables is to wrap
the array in a compound variable and use the "copy" operator
("dest=src"), e.g.
-- snip --
$ ksh93 -c 'compound x=( typeset -a ar=( 1 2 3 ) ) ; compound y ; y=x ;
print -v y'
(
typeset -a ar=(
1
2
3
)
)
-- snip --
David: Would it be possible to allow "dest=src" to be used for arrays,
e.g. that this works (assuming both "src" and "dest" are arrays of the
same type (e.g. doing copies between "integer -a src" and something like
"compound -a dest" should result in an error)):
-- snip --
integer -a src=( 1 2 3 )
# ...
integer -a dest
dest=src # copy array
-- snip --
----
Bye,
Roland
--
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