AST-Users
I also suspect that the ksh construct:
~(options :pattern-list )
is not working correctly. It doesn't seem to be interpreting the grep-
like regular expression thingies that actually require some
interpretation.
For example, with an exact match, using no grep-like regular
expression thingies that require some interpretation, it works
correctly:
$ [[ 'x' == ~(G:x) ]]; print $?
0
However, changing the x (inside the parens) to a dot, so that we use a
grep-like regular expression that does require some interpretation (a
simple dot character, to match any single character), ksh does not
evaluate it as I expect it to:
$ [[ 'x' == ~(G:.) ]]; print $?
1
Or am I misunderstanding the usage of:
~(options :pattern-list )
Dan
On Mar 28, 2010, at 12:55 AM, ольга крыжановская wrote:
In Solaris ksh93 (which has xgrep as built in utility) I get this:
(builtin xgrep ; print -- "-a -C" | xgrep '(.*-a.*)&(.*-C.*)')
-a -C
Glenn, is ~(X) broken in ast-ksh.2010-03-09?
Olga
2010/3/28 ольга крыжановская
<[email protected]>:
OK, I am getting crazy (maybe): Can anyone explain why ksh -c 'x="-a
-C" ; [[ "$x" == ~(Xlr)(.*-a.*)&(.*-C.*) ]] && print true' does not
print 'true"? Xlr selects an augmented extended regular expression,
.*-a.* should be a match, .*-C.* should be a match and & means AND.
I'm banging my head since an hour against the problem with no
success.
HELP, please.
Olga
--
, _ _ ,
{ \/`o;====- Olga Kryzhanovska -====;o`\/ }
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--
, _ _ ,
{ \/`o;====- Olga Kryzhanovska -====;o`\/ }
.----'-/`-/ [email protected] \-`\-'----.
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