2012/3/13 ольга крыжановская <[email protected]>
> Clark, ar=() creates an empty compound variable, not an array. > You can use typeset +p ar to see the typeset attributes currently > being defined for a specific variable. > Thanks. But how can I get an empty array when initializing an multi-dimensional array as this would not work typeset -a arr=( ( 11 22 33 ) ( ) ) > > As a rule of good shell script coding style, always declare variables > with non string types using typeset <typespec> <varname> before using > them. > > Olga > > On Tue, Mar 13, 2012 at 9:00 AM, Clark J. Wang <[email protected]> wrote: > > $ echo ${.sh.version} > > Version JMP 93u+ 2012-02-14 > > $ arr=( ) > > $ echo "$arr" > > ( > > ) <---- ??? > > $ typeset -a arr=( ) <-- But this works fine. > > $ echo "$arr" > > > > $ > > > > Another case: > > > > $ typeset -a arr=( ( 11 22 33 ) ( 44 55 ) ) > > $ arr[1]+=( 66 ) > > $ echo ${arr[1][@]} > > 44 55 66 > > $ arr[1]=( ) <-- Here I want to set arr[1] to an empty array > > ksh-20120214: 1: invalid variable name > > $ > > > > _______________________________________________ > > ast-users mailing list > > [email protected] > > https://mailman.research.att.com/mailman/listinfo/ast-users > > > > > > -- > , _ _ , > { \/`o;====- Olga Kryzhanovska -====;o`\/ } > .----'-/`-/ [email protected] \-`\-'----. > `'-..-| / http://twitter.com/fleyta \ |-..-'` > /\/\ Solaris/BSD//C/C++ programmer /\/\ > `--` `--` >
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