basically the trunking header is 10 bytes long the IAX header is 4 bytes log IP is 20 bytes UDP is 8 GSM is 33 bytes long (20 ms data)
So assuming that you send a packet every 20 ms (50 times a second) it goes like this: ((20+8+10) + x * (4 + 33))*50*8 = all_bandwidth [kbps] where x is the number of calls. (*8) because you come from bytes to bits. That doesn't include the transmission layer, only IP/UDP/IAX2/GSM regards Martin On Thu, 9 Oct 2003, duncan wrote: > > > > So whats the best way to find the maximum number of concurrent calls in > > > this setup: > > > > > > IAX2 Trunk using GSM over a 512k internet line. > > >show channels? > > actually i meant how to find out how many i could push down the 512k line - > with regards to codec bandwidth and signalling etc... > > > > > duncan > > _______________________________________________ > Asterisk-Users mailing list > [EMAIL PROTECTED] > http://lists.digium.com/mailman/listinfo/asterisk-users > _______________________________________________ Asterisk-Users mailing list [EMAIL PROTECTED] http://lists.digium.com/mailman/listinfo/asterisk-users
