With such a configuration, agents get to be available (on all queues) as soon as they log in and stop to be availbl when they log out. That's why youu use agents instead of, say, SIP/123. The other alternative is to have an agent join each queue dynamically via AddQueueMember() and then log off from each queue dynamically... but this leads to much larger agent control problems. :-)
l.

On Wed, 29 Mar 2006 14:59:15 +0200, Matt <[EMAIL PROTECTED]> wrote:

Ok,
Understood all this.. but isn't that for making 'static' agents?  What
if I want my agents to be able to log in/out of the queues... ie when
they are not here.

On 3/29/06, Lenz <[EMAIL PROTECTED]> wrote:

You just add the same agent to both queues (don't use groups), like in
queues.conf:

[queue1]
....
member=>Agent/101

[queue2]
...
member=>Agent/101

Now Agent 101 is a member of both queues, and will not be called while
s/he is on conversation.
l.



On Wed, 29 Mar 2006 09:02:11 +0200, Tomislav ParĨina <[EMAIL PROTECTED]>
wrote:

> In article <[EMAIL PROTECTED]>, [EMAIL PROTECTED] says...
>>
>> Just add the agent to both queues, * will take care of the rest.
>> l.
>
> I have tried to put agents in groups and then join groups to specific
> queue. It doesn't work. I don't know is the problem because one agent
> can't be in more groups or joining groups to queue's doesn't work.
>
> Do you know anything about this?
>
>
> --
> Tomislav Parcina
> tparcina#lama.hr




--
Loway Research - Home of QueueMetrics
http://queuemetrics.loway.it

_______________________________________________
--Bandwidth and Colocation provided by Easynews.com --

Asterisk-Users mailing list
To UNSUBSCRIBE or update options visit:
   http://lists.digium.com/mailman/listinfo/asterisk-users




--
Loway Research - Home of QueueMetrics
http://queuemetrics.loway.it

_______________________________________________
--Bandwidth and Colocation provided by Easynews.com --

Asterisk-Users mailing list
To UNSUBSCRIBE or update options visit:
  http://lists.digium.com/mailman/listinfo/asterisk-users

Reply via email to