I actually did get it to work, by removing _all_ spaces from the for line...
for (x=0;${x}<3;x=${x}+1) {
This works for me. It's just a matter of finding WHICH space is breaking it.
-----Original Message-----
From: Rushowr [mailto:[EMAIL PROTECTED]
Sent: Sat 7/29/2006 12:24 PM
To: 'Asterisk Users Mailing List - Non-Commercial Discussion'
Cc:
Subject: RE: [asterisk-users] AEL2 Looping
>> context new_pbx_betty_start {
>>
>> _X. => {
>> for (x=0; ${x} < 3; x=${x} + 1) {
>> Verbose(x is ${x} !);
>> }
>> };
>>
>> }
>I would have to see the output of "show dialplan new_pbx_betty_start"
to
know exactly >what is going on. However, I'm guessing that if you
remove
the space between the
>semicolon and the "x=${x} + 1", it will work.
>On pretty much everything except expression evaluation (such as ${x} <
3),
Asterisk
>is sensitive to whitespace. " x=${x} + 1" was most likely translated
directly into
>Set( x=$[${x} = 1]). That means you are setting the variable name, "
x",
including
>the leading space. That is not the same variable as ${x} which you are
using
>everywhere else.
Russel,
Stupid question, but isn't the AEL2 parser supposed to handle the above
code
first? Hypothetically, if the parser DOES handle the code the example
given
by Murf on voip-info (which is the exact code Douglas posted, other
than the
name new_pbx_betty_start) should work properly. Also, to answer your
question, removing the space does not help. I'm actually getting a bug
report together concerning this, and I tested it with and without
spaces in
multiple places in the for loop definition. I'd give examples but I
don't
have access right now.
Keep up the great work guys!
Rushowr
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