Arrrgh! You are correct, of course. I hadn't realised you could do it
that way - I was assuming it was a variable that was returned to the
Some of the finer points of AGI are still a slight mystery to me!
Thank you very much - working perfectly now, with your help and the
following code. Thank you again.
escape_digits = str("*")
if pressed_digit == "*":
On 11 October 2016 at 09:31, Lefteris Zafiris <z...@fastmail.com> wrote:
> On Mon, 10 Oct 2016, at 22:47, Jonathan H wrote:
>> For reasons best known to myself, I call a python agi (PYST2 - love
>> it!) which streams a series of very short files in quick succession.
>> Like this:
>> escape_digits = str("0")
>> and this is what I see on the AGI debug:
>> <Local/s@root-00000061;2>AGI Tx >> 200 result=0 endpos=6784
>> <Local/s@root-00000061;2>AGI Rx << STREAM FILE
>> /home/DefaultPrompts/en_GB/female/wx/low "0" 0
>> -- <Local/s@root-00000061;2> Playing
>> '/home/DefaultPrompts/en_GB/female/wx/low.alaw' (escape_digits=0)
>> (sample_offset 0) (language 'en_GB')
>> <Local/s@root-00000061;2>AGI Tx >> 200 result=48 endpos=1440
>> The FIRST line is a file that finished normally, with result=0, the
>> LAST line is a file that was interrupted, and receives result=48 from
>> Yes, zero stops the file playing, but it just goes onto the next file.
>> So, how do I get that variable? It doesn't become available in python,
>> and trying to get it via either
>> just makes python choke and the AGI quits. That would be fine if it
>> was a result of result being 48!
>> I feel like I'm going slightly bonkers here because it's something so
>> obvious, and yet I've googled so hard over this!
> as the docs on stream_file() mention it returns the digit if one was
> So you might want to try something like:
> pressed_digit = agi.stream_file(promptFile,escape_digits)
> in you case the raw value 48 is converted to its ascii equivalent so
> pressed_digit will have the value 0
> Lefteris Zafiris
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