----- Original Message -----
> Trying to pass ${EXTEN} to a php file for processing. Not sure how to.
> The php file takes $did_numb as defined:
>
>
> <?php
>
> $did_numb = $_GET['did_numb'];
> ?>
There are two ways to do this. If you insist on using a system() call you could
pass the variable as an aguement. I don't recall how to use the system()
function to pass an argument so I'll guess here:
exten => s,n,system(php file.php "${EXTEN}")
Then in PHP use:
#!/usr/bin/php
<?php
$did_numb = $_GLOBALS['argv'][1]
?>
>
> I know that http://serverIP/file.php?did_numb=416-444-5555 works fine
> but when calling php file by system() from dialplan how can this be
> done?
>
>
> exten => s,n,system(php file.php?did_numb=${EXTEN}) |||| This method
> doesn't work as "php file.php?did_numb=416-444-555" simply doesn't
> work from the CentOS prompt.
>
>
> What is the proper syntax here?
>
>
> I also want whatever that file.php returns to be saved in $var for
> later usage in dial-plan afterwards.
Okay so what you really want is to use AGI. Get an AGI library for PHP. I
recall using one called phpagi.php (http://sourceforge.net/projects/phpagi/)
You will want to use the get_variable() and set_variable() functions.
Again from memory:
exten => s,n,agi(file.php)
Then the PHP code
#!/usr/bin/php
<?php
// Use the phpagi library
require "phpagi.php';
// It's an object so let's instantiate it
$agi = new AGI();
// Get a variable from dial plan
$agi->get_variable($EXTEN);
// do something, like assign a value to $var
$var = "something";
// Set a dial plan variable
$agi->set_variable("var", $var);
exit(0);
?>
--
John Van Ostrand
CTO, co-CEO
Net Direct Inc.
564 Weber St. N. Unit 12, Waterloo, ON N2L 5C6
Ph: 866-883-1172 x5102
Fx: 519-883-8533
Linux Solutions / IBM Hardware
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