Hi Hongwei,
On Sat, Aug 20, 2016 at 1:44 PM, Hongwei Xi <[email protected]> wrote:
> If you do:
>
> val foo = $extval(struct_foo, "foo")
>
> the foo is a value (a flat record); it cannot be used as a left-value.
Thanks. It means the answer for following:
> Totally, `$extval` can only maintain viewtype as pointer. Is it right?
However, following code is using flat record with well-typed...
```
var buz: @{ a = int, b = ptr }
val () = buz.a := 1
```
Best regards,
--
Kiwamu Okabe at METASEPI DESIGN
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