> Hi Uwe,
> 2016-09-11 13:51 GMT+02:00 Uwe Brauer <[email protected]>:
> What do you mean by "does not work"? What do you expect? What's the
> behavior you see?
Take the following example using equations
\begin{equation}
\label{eq:6.3}
\left\{
\begin{array}{rrr}
u^{\nu}\nabla_{\nu}\epsilon + (\epsilon+p) \nabla_{\nu}u^{\nu} &= 0 \\
(\epsilon+p) P_{\alpha\beta}u^{\nu}\nabla_{\nu}{u^\beta} + P^\nu{}_\alpha
\nabla_\nu p &= 0 \\ u^\nu\nabla_\nu s & = 0
\end{array}\right..
\end{equation}
Rifilling leads to
\begin{equation}
\label{eq:6.3}
\left\{
\begin{array}{rrr}
u^{\nu}\nabla_{\nu}\epsilon + (\epsilon+p) \nabla_{\nu}u^{\nu} &= 0 \\
(\epsilon+p) P_{\alpha\beta}u^{\nu}\nabla_{\nu}{u^\beta} +
P^\nu{}_\alpha
\nabla_\nu p &= 0 \\ u^\nu\nabla_\nu s & = 0
\end{array}\right..
\end{equation}
Now I swore this did not work for \[\] last time I checked that is
\[
\label{eq:6.3}
\left\{
\begin{array}{rrr}
u^{\nu}\nabla_{\nu}\epsilon + (\epsilon+p) \nabla_{\nu}u^{\nu} &= 0 \\
(\epsilon+p) P_{\alpha\beta}u^{\nu}\nabla_{\nu}{u^\beta} + P^\nu{}_\alpha
\nabla_\nu p &= 0 \\ u^\nu\nabla_\nu s & = 0
\end{array}\right..
\]
However I just checked and indeed it seems to work, that is filling
produce the desired behavior.
\[
\label{eq:6.3}
\left\{
\begin{array}{rrr}
u^{\nu}\nabla_{\nu}\epsilon + (\epsilon+p) \nabla_{\nu}u^{\nu} &= 0 \\
(\epsilon+p) P_{\alpha\beta}u^{\nu}\nabla_{\nu}{u^\beta} +
P^\nu{}_\alpha
\nabla_\nu p &= 0 \\ u^\nu\nabla_\nu s & = 0
\end{array}\right..
\]
I will watch this however and once I see something odd I report back.
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