eiret;226237 Wrote: 
> 
> Binary numbers, just like decimal numbers, do not always multiply and
> divide evenly. There are often remainders - extra digits that are a
> result of the multiplication.

My point is very simple.  Rounding errors like that can only affect the
last digit.  So the worst thing that can happen is that the
volume-reduced result is off by an amount equal to half the 24th digit.
On the other hand the last three digits are lost in noise anyway for
the transporter (and it's worse for the SB).  So the distortion due to
noise is always at least 16 times the amplitude of the distortion
induced by the digital rounding.

Am I missing something?


-- 
opaqueice
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