Yes. I think there is no ambiguity. But we have to be careful about
that it's still arbitrary with respect to lattice translation. So for
this, we employ some convention, e.g., translation part (t) of a
symmetry operation is restricted 0 <= t < 1.
The decoding of Hall symbol is not difficult. You can do it following
http://cci.lbl.gov/sginfo/hall_symbols.html .

I still have not yet understood what you want to do. But there may be
other ambiguities, or say conventions. For example, there are reverse
and observe settings of hexagonal rhombohedral (hR),  which gives 60
degrees difference along c-axis, but gives, I guess, the same set of
symmetry operations for a space group type. So spg_refine_cell always
returns primitive rhombohedral (pR).

Togo

On Wed, Feb 12, 2014 at 5:09 PM, Jure Varlec <jure.var...@ki.si> wrote:
> On Wednesday 12 of February 2014 15:11:01 Atsushi Togo wrote:
>> Yes, right. As you wrote, spg_refine_cell put the cell into "an
>> appropriate state". There are several choices, but spgilb forces to
>> choose one of them.
>> A word "transformation" can be used to transform a setting (of axes,
>> origin, or centring) to another. So I need to make it clear.
>
> OK. What I want to make clear: do we expect spglib and OpenBabel to have the
> same "appropritate state" for the same Hall symbol, or is it OK for them to
> have a different setting? In other words, does a Hall symbol specify the
> setting completely, or is there some ambiguity left?
>
> Regards
> Jure
>
>
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-- 
Atsushi Togo
http://atztogo.github.com/
atz.t...@gmail.com

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