> The native int size on your x86 compiler is probably 32 bits. Each > argument to the shift is promoted to int first; that's the bit about > "integer promotions" and this gets you answer you're expecting. I > believe the native int size on avr-gcc is 16 bits, so your left operand: > > ((uint16_t)0xffffL) > > stays at 16 bits on the AVR.
Ok, thanks for bearing with me... I had been under the impression that shift requires both operands to have the same width (there are web pages that appear to say this), but a close read of the spec says that the result of a shift is the type of the promoted left operand. John Regehr _______________________________________________ AVR-GCC-list mailing list AVR-GCC-list@nongnu.org http://lists.nongnu.org/mailman/listinfo/avr-gcc-list
