> > > > > In C there are 3 char types. "char" "signed char" "unsigned char" so > maybe "char" isn't signed?
Ok, so that leaves me VERY confused.. Correct me if I'm wrong, but "signed" variables use the high bit to indicate negative by setting it to a 1, correct? So, I can only see two options, either you do, or you don't. Char has to equate to signed char, or unsigned char, doesn't it?
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