Probably the fastest and easiest way yes. http://en.wikipedia.org/wiki/Power_of_two#Fast_algorithm_to_check_if_a_positive_number_is_a_power_of_two
On 27 apr, 17:58, rjgtav <[email protected]> wrote: > Hi. While searching on the web, i found that there is another (less > complicated - for me) way to check if the value is Power of two: > > return (value & (value - 1)) == 0; > > What do you think?
