Tim, No. You are integrating the wrong expression. You wrote:
integrate(1/(-3+v^3)*v/(-4*v^3)^(1/2),v) but William wrote: integrate(1/(-3+v^3)*v/(-4+v^3)^(1/2),v) When you re-keyed it you changed + to * in the following sub-expression, i.e. (-4+v^3) to (-4*v^3) The integral presented in issue #361 still fails in newer versions of Axiom. Regards, Bill Page. On 9/8/07, William Sit <[EMAIL PROTECTED]> wrote: > Thanks. In that case, the report file should be closed (assuming the integral > is > correct). > > William > > [EMAIL PROTECTED] wrote: > > > William, > > > > I notice that you're running a version of Axiom from Nov 2004. > > In the latest version I get: > > > > Starts dribbling to bug361.input (2007/9/8, 20:55:12). > > (1) -> )set mes auto off > > (1) -> integrate(1/(-3+v^3)*v/(-4*v^3)^(1/2),v) > > ... _______________________________________________ Axiom-developer mailing list [email protected] http://lists.nongnu.org/mailman/listinfo/axiom-developer
