Just found the answer - by reading the doc... ;-) I understand that the singular point is where dp/dx=dp/dy=0, which is true in (0,0). I guess this is an issue for the plotting algorithm...
Francesco On Fri, Aug 28, 2009 at 9:33 AM, Francesco Pedulla' <[email protected]>wrote: > Dear all, > I am a newcomer to Axiom, please pardon me if my question is trivial. Here > follows the dialogue with Axiom I do not understand: > > (1) -> p:=((x**2+y**2)**2-x*y) > > 4 2 2 4 > (1) y + 2x y - x y + x > Type: Polynomial > Integer > > (2) -> draw(p=0,x,y,range==[0..0.5,0..0.5]) > > >> Error detected within library code: > singular pts in region of sketch > > I cannot see the singular point in "p". Any help? > > Francesco > >
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