I don't know about a specialized solution (outside of Taylor series), but as I recall making change and counting such is the first example in: http://www.msri.org/communications/vmath/special_productions/production1/index_html Sturmfel's excellent elementary introduction to Grobner Bases; which Axiom does have support for.
Ray Nicolas FRANCOIS wrote: > Hi. > > Is there any way to obtain the decomposition in simple elements (don't > know exactly how to say this in english) of a fraction of the form : > > 1 > ------------------- > (1-X)(1-X^2)(1-X^5) > > (to obtain its formal series equivalent \sum a_nX^n, a_n being the > number of ways to pay n€ using 1, 2 and 5€ corners (no, there > is no such thing as a 5€ corner, but there's a 5€ banknote !)). > > I'd like to obtain the C-decomposition, what do I have to do ? > > More precisely : is there a way to force the use of an extension of > Q(X), by adding roots like exp(2*I*PI/5) or sqrt(2) ? > > \bye > > PS : clearly I'm not very good at using Axiom documentation ! > > _______________________________________________ Axiom-math mailing list [email protected] http://lists.nongnu.org/mailman/listinfo/axiom-math
