Hi Etienne,
You can do something like this.
In your service class you can have init(ServiceContext) method which
is called by Axis2. You can use serviceContext like this.
public class ServiceClass {
public void init(ServiceContext serviceContext) {
ServletContext servletContext = (ServletContext)
serviceContext.getProperty("transport.http.servletContext");
servletContext.getResourceAsStream("/WEB-INF/path/file");
}
...
}
Hope this helps.
Upul
On Nov 13, 2007 1:29 AM, Etienne Dube <[EMAIL PROTECTED]> wrote:
> Hello,
>
> I'm looking for a way to retrieve the local path where an Axis2 service
> is deployed. In my case, it is located in
> C:\java\Tomcat6\webapps\axis2\WEB-INF\services\MyService . I deployed it
> as a directory instead of an .aar archive for performance reasons (I use
> lots of external JARs and class loading is too slow when deploying as an
> .aar). In the code of my service class, I need to open a file located in
> the root of the service directory structure. For the moment I'm using a
> hard-coded path, but I'd like to handle this in a more graceful manner.
> Is there a way to do what I want? I'm using Axis2 version 1.3.
>
> Thank you in advance,
>
> Etienne
>
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: [EMAIL PROTECTED]
> For additional commands, e-mail: [EMAIL PROTECTED]
>
>
---------------------------------------------------------------------
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
