That doesn't address directly your problem, but I strongly recommend you have a look at Jakarta Commons Exec. It will save you lots of trouble.
http://commons.apache.org/ 2009/11/27 Kevin Alonso <kalo...@vicomtech.org> > I get the path of the file: > > URL url = > getClass().getClassLoader().getResource("ColorClusteringFroga.exe"); > > String path = url.getPath(); > > (Path: C:/Program Files/Apache Software Foundation/Tomcat > 6.0/temp/axis2-tmp-5629 > 138317308731761.tmp/axis2593833549232759380WebService.aar!/execution.ex > e) > > But when I put it to execute: > > Process p = Runtime.getRuntime().exec(path); > > > I receive the following error: > > java.io.IOException: Cannot run program "C:/Program": CreateProcess > error=2, The > system cannot find the file specified > > I think that it is becouse of !/ > > Any idea to solve this? > > Thank you in advance. > > Kevin. > > > Deepal jayasinghe escribió: > >> One way to do this is you can put the exe file somewhere else and you >> can define the location from a parameter (in services.xml) and then use >> the value of the parameter to load the exe file. One other way is you >> can get the URI of the exe file from axisservice, and you may try to >> execute it from that >> >> classloader.getResource("execution.exe") >> >> Thanks, >> Deepal >> >>> Hello, >>> >>> I have a web service that needs to call an .exe file and it is into >>> the .aar file. >>> >>> How can I do this? Which is the path I have to use in the instruction... >>> >>> Process p = Runtime.getRuntime().exec("execution.exe"); >>> >>> Is there another way to do this? >>> >>> Thank you in advance. >>> >>> Kevin. >>> >>> >> >>
