Unable to find Deserializer

[Vijetha Vadlakonda \(vijetha\)]

Title: Message

Hi,

 

I have an element, say XYZ, which was a part of an XSD file and used to referred using one namespace, say xmlns:axl="http://www.abc.com/AXL/1.0". But,later I moved it into the WSDL file and refer to it usinf this namespace, namely, xmlns:axlapi="http://www.abc.com/AXLAPI/1.0".

 

I then ran the WSDL2Java tool on this WSDL file and got the stubs. Everything went fine. Then, I created the Client which uses the XYZ element. But when I run the client, it gives out an error as follows,

 

org.xml.sax.SAXException: No deserializer for {http://www.abc.com/AXL/1.0}XYZ
        at org.apache.axis.encoding.DeserializerImpl.onStartElement(Deserializer
Impl.java:447)
        at org.apache.axis.encoding.DeserializerImpl.startElement(DeserializerIm
pl.java:394)
        at org.apache.axis.encoding.DeserializationContextImpl.startElement(Dese
rializationContextImpl.java:906)
        at org.apache.axis.message.SAX2EventRecorder.replay(SAX2EventRecorder.ja
va:200)
        at org.apache.axis.message.MessageElement.publishToHandler(MessageElemen
t.java:684)
        at org.apache.axis.message.RPCElement.deserialize(RPCElement.java:241)
        at org.apache.axis.message.RPCElement.getParams(RPCElement.java:265)
        at org.apache.axis.client.Call.invoke(Call.java:1871)
        at org.apache.axis.client.Call.invoke(Call.java:1777)
        at org.apache.axis.client.Call.invoke(Call.java:1315)
        at com.cisco.axlapi.AXLAPIBindingStub.getPhone(AXLAPIBindingStub.java:20
42)
        at com.cisco.axlapi.PhoneClient.main(PhoneClient.java:31)

 

How come it is looking for the Deserializer for {http://www.abc.com/AXL/1.0}XYZ when I use {http://www.abc.com/AXLAPI/1.0}XYZ ?

 

Please help. I have no clue as to what might me happening and it is pretty urgent.

 

Thanks

Vijetha