Re: xsl:call-template question

[Christian Jaeger]

ok, Kip explained me everything in irc. (Looks like I'm still an XSLT 
newbie - not that this would surprise me. But to be fair to myself: 
it looks like even some article authors haven't understood xsl, like 
of the one I linked in my mail)

Correct is:

  <xsl:template name="allexceptentry">
    <xsl:copy-of select="$main"/>
  </xsl:template>
  <xsl:call-template name="allexceptentry">
    <xsl:with-param name="main">
        ..<foo>...</foo>..
    </xsl:with-param>
  </xsl:call-template>
Christian.

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