On Mon, 12 Sep 2011 12:09:01 +0200
francesco.gring...@ing.unibs.it wrote:
> but trying on a = 0x8000 and b = 0x7fff helped me understanding. a - b =
> 0x8000 + 2'(0x7fff) = 0x0001 > 0. While 0x8000 < 0x7fff.
I don't get it.
Can you write simple pseudocode for your instruction?
For example, for jls, we have this pseudocode:
if (xxx < yyy)
pc := jjj
(where xxx and yyy are two's complement)
What does jdX do in C-pseudocode?
http://bcm-v4.sipsolutions.net/802.11/Microcode
--
Greetings, Michael.
_______________________________________________
b43-dev mailing list
b43-dev@lists.infradead.org
http://lists.infradead.org/mailman/listinfo/b43-dev
