>>>>> On Mon, 28 Nov 2005 17:06:00 +0100, Kern Sibbald <[EMAIL PROTECTED]> said:
Kern> On Monday 28 November 2005 15:55, Martin Simmons wrote:
>> >>>>> On Fri, 25 Nov 2005 09:21:29 +0000, Greg Cope <[EMAIL PROTECTED]>
>> >>>>> said:
>>
Greg> I am trying to glob a load of oracle backup files. As per Stephan
Greg> Ebelt's post these will be under /uNN dirs that are often on
>> different Greg> file systems.
>>
Greg> What I am trying to do is;
>>
Greg> regex = "^\/u[0-9]{2}\/(oraback|oraarch)"
>>
Greg> But the following fail to match anything bar '/'
>>
Greg> regex = "^\/u[0-9]{2}\/(oraback|oraarch)"
Greg> regex = "^\/u[0-9]{2}\/oraexp"
Greg> regex = "^\/u[0-9]{2}\/oraback"
Greg> regex = "^\/u[0-9]{2}.oraback"
>>
Greg> As expected regex = "^\/u[0-9]{2}" matches the lot.
>>
Greg> Can anyone shed any light on this or the regex code?
>>
>> The problem is that Bacula walks down the tree of directories looking for
>> matching include/exclude patterns. When it finds an excluded directory, it
>> doesn't look any deeper in that directory. Now /u02 doesn't match any of
>> the above, so it stops the walk before /u02/oraback is found.
>>
>> BTW, I don't think you need \ before / in a regex.
Kern> Recently, I added something similar to this example to the FileSet
chapter of
Kern> the manual. It would be interesting to know what you think about the
example
Kern> Martin since I haven't actually "run" it. Of course, the example
doesn't
Kern> deal with more complex issues such as traversing subdirectories where
parents
Kern> may be excluded ...
I found the new examples, but what the ^.?*$ is "^.?*$" supposed to mean? :-)
As the manual mentions in a previous example, this regexp doesn't compile on
FreeBSD, so the example won't work. Maybe you just want ".*", i.e. match
anything?
__Martin
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