I have written four solutions to a problem(self explanatory) ,out of them ,which one is the pythonic way of doing and is there any other ways of solving it? 1.sum([i for i in range(1000) if i%3==0 or i%5==0])
2.gen=(i for i in range(1000)) sum([i for i in gen if i%3==0 or i%5==0]) 3.sum(filter(lambda a:a%3==0 or a%5==0,range(1000))) 4.def generator(m): count=0 while count<m: if count%3==0 or count%5==0: yield count count+=1 sum([i for i in generator(1000)]) Regards, ~ Srini T _______________________________________________ BangPypers mailing list BangPypers@python.org http://mail.python.org/mailman/listinfo/bangpypers