Shashidhar Paragonda <[email protected]> writes:
> Dear Python hackers,
>
> I have a text file and the contents are like :
>
> #(
> #resultToExportToCurveDistDialog ' ->'
> #off)
>
> like same structure many lines exists.
> My requirement is I want to find line where
> "resultToExportCurveDistDialog" and other pattern exist. After that I need
> to fetch the value of it. in above example value
> for "resultToExportCurveDistDialog" is "off" how to move file
> pointer to next line and fetch value as soon as i find my required patterns.
> Thank you in advance for the help.
Something like this? Untested.
keywords = set(["resultToExportToCurveDistDialog",
"resultToExportCurveDistDialog2"...])
with open("file.txt", r) as f:
for line in f:
keyword = line.strip("#").split()[0].strip()
if keyword in keywords:
value = f.next()
print "%s : %s"%(keyword, value)
--
~noufal
http://nibrahim.net.in
A verbal contract isn't worth the paper it's written on. Include me out.
-Samuel Goldwyn
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