Noufal,
I tried with :
{{{
import urllib, urllib2, cookielib
username = 'xxx'
password = 'xxx'
savepage = open('output.html', 'w')
#cj = cookielib.CookieJar()
#opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(cj))
opener = urllib2.build_opener(urllib2.HTTPCookieProcessor())
login_data = urllib.urlencode({'username' : username, 'j_password' :
password})
opener.open('https://ebpp.airtelworld.com/pkmslogin.form', login_data)
resp = opener.open('
https://ebpp.airtelworld.com/cares/wps/myportal/!ut/p/.cmd/cs/.ce/7_0_A/.s/7_0_J5/_s.7_0_A/7_0_J5
')
savepage.write(resp.read())
savepage.close()
}}}
The link in the 'resp' is true to my knowledge. I checked it by logging in
at diff times. Its coming the same every time and it is the link behind
'Account Information' which comes on the front page after logging in.
When I open output.html, Its giving me the same login form i.e same looks
as those of 'https://ebpp.airtelworld.com/pkmslogin.form'
I tried with CookieJar() also. Same results.
Any ideas?
Thanks,
Nikunj
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On Fri, Dec 23, 2011 at 1:29 AM, Saager Mhatre <saager.mha...@gmail.com>wrote:
> On Thu, Dec 22, 2011 at 10:27 PM, Noufal Ibrahim <nou...@gmail.com> wrote:
>
> > [snip]
> >
>
> >
> The Python stdlib can handle this using urllib2 and cookielib. I've managed
> > something like this here
> https://gist.github.com/3811b566df4005a012c7which you can use as a
> starting point.
> >
> > After this, you have a session. Now you should be able to GET the URL you
> > want directly and parse it for the information you need.
> >
>
> Wouldn't something like mechanize
> <http://pypi.python.org/pypi/mechanize>simplify all this?
>
> - d
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