On Tuesday 04 December 2012 10:55 AM, Anand Chitipothu wrote:
What is really weird is that the class body is evaluated without considering the enclosed scope, but the methods defined in the class have access to the enclosed scope.Found the culprit. Lets looks at the following code. code = """ x = x+1 def f(): return x print(x, f()) """ x = 5 exec(code) x = 5 exec(code, globals(), {}) When exec is called without any locals, it works as we expected and x in f is bound to the x in the code. But when we supply a locals dict to exec, it behaves differently. The x in f is bound to global x. I'm not sure why we have this confusing behavior.
Here's your answer: http://stackoverflow.com/questions/291978/short-description-of-python-scoping-rules cheers, - steve _______________________________________________ BangPypers mailing list BangPypers@python.org http://mail.python.org/mailman/listinfo/bangpypers
