Hi, Sorry silly math typo: Thomas DeWeese wrote:
Quadradic = (1-t)^2*Pq1 + 2*t(1-t)*Pq2 + t^2Pq3 Cubic = (1-t)^3*Pc1 + 3*t(1-t)^2*Pc2 + 3*t^2*(1-t)Pc3 + t^3Pc4 Pc1 = Pq1 Pc2 =(Pq1 + 2*(Pq2-Pq1)/3) Pc3 =(Pq3 + 2*(Pq2-Pq3)/2)
^ should be '3':
Pc3 =(Pq3 + 2*(Pq2-Pq3)/3)
Pc4 = Pq3
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