Hi Nacho, Thomas, I have been playing around in order to find a solution to this problem, which I have, so far, not encountered, but I have made a few observations which I would like to share:
In theory, I would picture the "printing with rendering transform" as the following sequence: 1) Retrieve the viewBox of the SVG document, i.e. a rectangle which spans the whole SVG document. 2) Retrieve the renderingTransform of the JSVGComponent (or whatever else one is using). 3) Compose both to obtain a viewBox on which the renderingTransform is applied--- this is the area of interest. 4) Give the printTranscoder the hints related to the area of interest and transcode. In practice, I am stumbling over steps 1 and 3. Nacho, in your code, I don't understand why you are doing Rectangle canvasRectangle = svgCanvas.getBounds(); Afaik this gives you the bounds (width & height) of the _component_ as it is laid out on screen, not of the SVG content of the component--- i.e. the width and height will be the size of the svg canvas component as it is laid out on screen! As Thomas has stated, I guess this is where the confusion about what is the area of interest comes in. I further guess that we both want a rectangle which gives coordinates within the viewBox (or simply the viewBox itself). In the files I am using, the viewBox is actually a no-op (exported from Visio, has attributes such as height="55.3642in" width="73.8189in" viewBox="0 0 5314.96 3986.22"). I could not figure out a way how to do it. Then, I also don't understand why there is a need for inverse transforms (because I simply don't know much about computer graphics in general, so this information might be totally irrelevant)... I did, however, uncomment that part, and printing without the inverse transforms applied at least prints something (and not a white sheet of paper), though I not the current renderingTransform of the SVG document. I just wanted to share these observations. Help would be, in any case, greatly appreciated. Thanks, Chris -- Chris Cruzdal __________________________________ Do you Yahoo!? Yahoo! Search - Find what you’re looking for faster http://search.yahoo.com --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
