KE Gan wrote:
(2) Use the inherited org.w3c.dom.Element.getElementByTagName() to get
the list of nodes with the same tag name.
You probably need to use the 'getElementByTagNameNS' calls and
use the SVG Namespace to find SVG elements.
(3) Use the org.w3c.dom.Element.getElementByTagName(), then use cast
the node to the appropriate class. Eg,
NodeList list = root.getElementsByTagName("rect");
Same comment on namespace stuff...
for(int i = 0; i < list.getLength(); i++) {
SVGRectElement rect = (SVGRectElement)list.item(i);
Yup!
Still ... must I type the string "rect" at --
root.getElementsByTagName("rect"); -- Is there a string constant I can
refer somewhere ?
Batik has a bunch of constants classes you can use:
org.apache.batik.util.SVGConstants
XMLConstants
CSSConstants
The SVGConstants class has constants for all of the SVG elements
(as well as the SVG Namespace).
(4) By the way, what is the different between SVGRect and SVGRectElement ?
SVGRect is used for things like bounding boxes and has no
element/node that participates in the DOM tree. The SVGRectElement
is the DOM representation of an SVG 'rect' element.
(1) The sample in Batik's website show that to get a SVGDocument
instance, I have to cast from a org.w3c.dom.Document, which in turn I
obtain from SAXSVGDocumentFactory.
String parser = XMLResourceDescriptor.getXMLParserClassName();
SAXSVGDocumentFactory f = new SAXSVGDocumentFactory(parser);
InputStream is = new FileInputStream("svgdom\\resource\\sample.svg");
Document doc = f.createDocument(null, is);
SVGDocument svgDoc = (SVGDocument)doc;
Is this the most appropriate way ? Can I load a SVG file (into
SVGDocument) without using org.w3c.dom.Document as the medium ?
Well it's not like the cast 'changes' the doc it's just
going from a baseclass to a subclass. As Tonny mentioned there
are interfaces on the SAXSVGDocumentFactory that return an
SVGDocument. The DOM is quite font of returning baseclasses
and requiring downcasting.
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