On Oct 9, 4:41 am, Ronald J Kimball <[EMAIL PROTECTED]> wrote:
> Here's how that would look in this case:
>
> ^(.)(?!\1)(.)(?!\1|\2)(.)\r
>
> Ronald
This does not work in 'process lines containing' for it to work there
you need to use this (note use $ rather than \r):
^(.)(?!\1)(.)(?!\1|\2)(.)$
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