Give this a try for the find. It worked for me. As a note, I
simplified some of the pieces.
<name>ACTIVE LOG\d+</name>
<trkseg>
<trkpt lat\=\"([\d\.]+)\" lon\=\"(\-?[\d\.]+)\">
<ele>([\d\.]+)</ele>
<time>(.*?)</time>
</trkpt>
-Kendall
On May 20, 4:00 pm, BBEdit user <[email protected]> wrote:
> I'm very much an amateur with grep.
>
> How do I find the optional minus and put it in the subpattern?
>
> I want to grab the time in the following and then use it for the name.
> Multiple names in the document. I seem to have it except for finding
> the optional minus sign that can occur with ele, lat and lon. I've
> only tried for lon so far and once I have the answer I'll expand it to
> the others. I get errors if I put the minus within the parentheses. I
> tried a -? within the parentheses too. How do I find the optional
> minus and put it in the subpattern?
>
> Typical document snippet (.gpx which is XML):
>
> <name>ACTIVE LOG133853</name>
> <trkseg>
> <trkpt lat="33.846701" lon="-118.387723">
> <ele>16.652</ele>
> <time>2010-05-15T20:38:53Z</time>
> </trkpt>
> </trkseg>
> </trk>
> <trk>
> <name>ACTIVE LOG133905</name>
> <trkseg>
> <trkpt lat="33.846273" lon="-118.387273">
> <ele>16.697</ele>
> <time>2010-05-15T20:39:05Z</time>
> </trkpt>
> <trkpt lat="33.846477" lon="-118.387105">
> <ele>16.652</ele>
> <time>2010-05-15T20:39:10Z</time>
> </trkpt>
> <trkpt lat="33.846606" lon="-118.387037">
> <ele>17.152</ele>
> <time>2010-05-15T20:39:16Z</time>
> </trkpt>
> <trkpt lat="33.846673" lon="-118.387212">
> <ele>17.294</ele>
> <time>2010-05-15T20:39:23Z</time>
> </trkpt>
> <trkpt lat="33.846595" lon="-118.387456">
> <ele>16.901</ele>
> <time>2010-05-15T20:39:29Z</time>
> </trkpt>
>
> My find:
> <name>ACTIVE LOG[1-9]+</name>
> <trkseg>
> <trkpt lat\=\"(\d+\.\d+)\" lon\=\"\-(\d+\.\d+)\">
> <ele>(\d+\.\d+)</ele>
> <time>(.*?)</time>
> </trkpt>
>
> My replace
> <name>\4 ACTIVE LOG</name>
> <trkseg>
> <trkpt lat=\"\1\" lon=\"\2\">
> <ele>\3</ele>
> <time>\4</time>
> </trkpt>
>
> This doesn't give errors but I can't find the optional minus and put
> it back in the replace. Maybe I'm going at this all wrong.
>
> Thanks for any help.
>
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