Dave Ratcliffe <[email protected]> sez: >I'm trying to replace the following sort of strings in a very large >text file (where "some_text" is one or more of any group of printable >characters, and "$" is eol): > [example elided] > >And I'm trying, unsuccessfully, to remember how to write the >expression in the Find: text box of the Find window that uses the '^' >character in both forms as "beginning-of-line" and as the "not" >operator.
In general, ^ means "beginning of line" when you use it directly within the pattern, and means "not" when you start a character class with it. For example, ^foo$ will match any line whose contents are "foo", while [^aeiou] will match any character which is not a vowel. (Please see Chapter 8 of the PDF manual: Help -> User Manual for more details on this, and lots of related info. :-) In this specific case: >In English, it would be writing a regular expression for >something like: > >For every occurrence of not-the-beginning-of-line, followed by "</p>", >insert a line feed in front of "</p>". > since by default . does not match linebreaks, you can do this: search for: (.)</p> replace with: \1\r</p> Regards, Patrick Woolsey == Bare Bones Software, Inc. <http://www.barebones.com> P.O. Box 1048, Bedford, MA 01730-1048 -- You received this message because you are subscribed to the "BBEdit Talk" discussion group on Google Groups. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at <http://groups.google.com/group/bbedit?hl=en> If you have a feature request or would like to report a problem, please email "[email protected]" rather than posting to the group. Follow @bbedit on Twitter: <http://www.twitter.com/bbedit>
