Am 08.07.2012 um 8, 13:59 schrieb Mosby: > I have data that looks similar to this... > > 75092 Sherman 1811 Whao > 75090 Sherman . at. 8am > 3244 Dripping Springs Rd > 903-647-3292 veryt > 75092 Sherman 3204 M > 75409 Anna Tooehold item > > There are tabs after the zip codes. > > I want to skip the zip codes and only find the lines that do not begin with a > zip code. Once those lines are located I want to remove the return at the > end of the previous line and replace it with a space. Every GREP pattern I > have tried to use always finds the zip code as well. There are tabs only > after the zip codes, no tabs are found on the other lines. > > Thanks for any help.
Additional to the fine solutions already given: If you can bear doing two search-replace operations (and assuming the whole file contains only lines as in your example): Step 1) search: \r replace: ' ' (<-- a space, without the brackets) --> this removes all line breaks in the file Step 2) search: (\d+\t) replace: \r\1 --> this puts line breaks back in, just before every zip code leaving only lines that start with a zip codes. I don't think, this solutions is better than the others, I just wanted to show, that there are several ways to solve a grep problem. I know, for real grep masters the challenge lies in finding a pattern that solves the problem in one go but for me (having only limited grep fu) finding a simple, more comprehensible solution has it's appeal, too. Regards, Roland -- You received this message because you are subscribed to the "BBEdit Talk" discussion group on Google Groups. To post to this group, send email to bbedit@googlegroups.com To unsubscribe from this group, send email to bbedit+unsubscr...@googlegroups.com For more options, visit this group at <http://groups.google.com/group/bbedit?hl=en> If you have a feature request or would like to report a problem, please email "supp...@barebones.com" rather than posting to the group. Follow @bbedit on Twitter: <http://www.twitter.com/bbedit>
