At 08:18 -0700 10/05/2012, jmichel wrote:
>I have a file consisting of groups of lines (unknown number of lines in
>each group).
>Each line begins by a 6 digit number, followed by an unknown sequence of
>words and numbers.
>Consecutive lines starting with the same number form a group.
>My problem is to combine lines from each group into a single line, keeping
>only the first occurrence of the distinctive number.
>I have been able to "find" groups using the pattern
>(\d{6})(.+)(?:\r\1(.+))+
>
>However, this does not appear to store the expressions matching the inner
>parentheses into separate variables.
>
>Is there a way to achieve the desired replacement using grep?
Provided I understand the task correctly, though your pattern should match
all such groups of lines, I don't see any way to restructure the matched
text in a single step.
(A relatively easy brute force solution would be to concatenate all
matching line pairs, then rinse & repeat. :)
As to your question about storage:
Though the contents of that inner subpattern (.+) are being captured N
times (where N is the number of lines within the match), only the last
instance matched will be stored and available by reference to that
subpattern.
[ As an aside for anyone else who may be wondering, this part of
the pattern (?: ) consists of `non-capturing parentheses` which
do not themselves store matched text. ]
For example, if you apply the following search & replace patterns:
Find: (?:(\d{6})\r)+
Replace: \1
to this text:
111222
333444
555666
the result will be:
555666
Regards,
Patrick Woolsey
==
Bare Bones Software, Inc. <http://www.barebones.com/>
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