Here is what I came up with: find: ((foo=".*?")\s(bar=".*?")?) replace: \2 bar="whatever"
Note that there is a space after the final quote. Cheers! Spencer -- This is the BBEdit Talk public discussion group. If you have a feature request or would like to report a problem, please email "[email protected]" rather than posting to the group. Follow @bbedit on Twitter: <http://www.twitter.com/bbedit> --- You received this message because you are subscribed to the Google Groups "BBEdit Talk" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected].
