Here's a working example:
set myText to "1. What's New with Joomla! 3 Templates 12m 9s\nInstalling
the starting state exercise files 6m 17s\nExploring template changes in
Joomla! 3 2m 11s\nDiscussing CSS and LESS 3m 41s\n\n2. Creating the HTML
Starting File 33m 13s\nReviewing the graphic designs 3m
0s\nUnderstanding Joomla! template file structures 5m 22s\nConfiguring a
Dreamweaver site and populating it with Bootstrap CSS 9m 48s\nBuilding
the grid 10m 11s\nAdding the Google font 2m 50s\nAdding a custom style
sheet 2m 2s\n"
--But you'd probably capture it with a selection. This script assumes
that the first line will be a valid first chapter starting with an
integer, and that none of the subsections already starts with a number.
set myNewTextList to {}
repeat with myItem in paragraphs of myText
tell myItem
if (count words) > 0 then
try
set myNumber to word 1 as integer --If this fails,
nothing else up to the "on error" executes.
set myNumberString to word 1
set myIncrement to 0
set end of myNewTextList to myItem & "\r"
on error
set myIncrement to myIncrement + 1
if myIncrement < 10 then
set mySubIncrementString to ".0" & (myIncrement as
string) & " "
else
set mySubIncrementString to "." & (myIncrement as
string) & " "
end if
set myNewIncrement to myNumberString & mySubIncrementString
set end of myNewTextList to myNewIncrement & myItem & "\r"
end try
else
set end of myNewTextList to "\r"
end if
end tell
end repeat
set myText to myNewTextList as string
return myText
---------------------
On 12/14/14 9:57 PM, Rick Gordon wrote:
To my knowledge, you could not do this with regex alone, but it would
be easy to do in any scripting language. (I'd use AppleScript, but
only because I know it reasonably well, so it's my go-to language.)
But it should be easy in Perl, Python, or any of the other likely
options, as well.
Rick Gordon
___________________________________________
RICK GORDON
EMERALD VALLEY GRAPHICS AND CONSULTING
___________________________________________
WWW: http://www.shelterpub.com
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