On Mar 31, 2015, at 02:09, Jean-Christophe Helary
<[email protected]> wrote:
>
> Is there a way to do something like this:
>
> search for (\d)
> replace by \1+1
______________________________________________________________________
Hey Jean-Christophe,
As far as I know regex cannot be made to do that, but through the magic of
Perl...
#! /usr/bin/env perl
use strict; use warnings;
#----------------------------------------
while (<>) {
s/\d+/@{[$&+1]}/g;
print;
}
See this page on StackOverflow for discussion.
--
Best Regards,
Chris
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