You need only add a leading zero to the first backreference to
make it unambiguous and ensure the following zero is treated
literally, i.e.
Replace: \020\1
since \2 and \02 both refer to the second subpattern.
Regards,
Patrick Woolsey
==
Bare Bones Software, Inc. <http://www.barebones.com/>
On 11/3/16 at 1:56 PM, [email protected] (Thomas
Falk) wrote:
Hi there,
i have a rather "simple" grep problem. I would like to add a
zero between 2 strings and cannot figure out how to write the
replacement pattern.
Say, the line is
foobar
My regex find is
(foo)(bar)
So: How to escape the "0" to get "bar0foo"?
\20\1 is obviously wrong.
Yours
Tom
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