On 10/2/19 at 5:01 AM, [email protected] (David Rostenne) wrote:
I was hoping for an alternative to the & in the replacement
strung that means ‘entire source line’ but this works perfectly.
Surround the whole pattern with parentheses. That will then be
the capture contained in \1. You will then have to increment
each other capture by 1.
Original:
http://ftp.newedinburgh.ca/wp-content/uploads/2019/09/1976_04-April-New-Edinburgh-News_web.pdf
Pattern:
(.+?/2019/[019]+/([0-9]+)[_.]([0-9]+)-([a-zA-Z]+).*\n)
Replacement:
\4 \2, NEN PDF, \2/\3/01, \1
Result:
April 1976, NEN PDF, 1976/04/01,
http://ftp.newedinburgh.ca/wp-content/uploads/2019/09/1976_04-April-New-Edinburgh-News_web.pdf
Note that the above pattern includes the end of line ("\n"); if
you don't want that, move the closing parenthesis to before the "\n".
HTH
--
- Bruce
_bruce__van_allen__santa_cruz__ca_
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