Find: (\d)|\[(\d{2})\]
Replace: \1\2\n (or just \1\2 if using "Extract")
Either \1 or \2 will be empty, so no harm in including both in the replacement.
On 29 Jul 2021, at 1:19, Tim A wrote:
> How to not include the brackets as Howard asked? I figure it involves
> non-capture but it eludes me.
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