Find:
(?<=/)(?:d([^\s/]|\\\x20)*?\.zip)\b
Or commented:
(?x) (?# Use multi-line and comments)
(?<=/) (?# Look behind a slash not including it in the match)
( (?# Start of capture \1)
d (?# Literal 'd')
(?: (?# Start non capturing parentheses)
[^\s/] (?# NOT [whitespace or slash] character)
| (?# or)
\\\x20 (?# Backslash escaped space)
) (?# End non capturing parentheses)
*? (?# Match 0 or more greedily)
\. (?# Literal '.')
zip (?# Literal 'zip')
) (?# End of capture \1)
\b (?# Word boundary)
Should match:
ftp://ftp.scene.org/pub/demos/artists/0xf/drunkchessboard.zip
ftp://ftp.scene.org/pub/demos/artists/0xf/d.zip
"ftp://ftp.scene.org/pub/demos/artists/0xf/d0xf+==&.zip";
/path/to/unicode/files/d你好.zip
/path/to/document\ with_escaped_space.zip
Should NOT match:
ftp://ftp.scene.org/pub/demos/artists/0xf/d.zipped -- Wrong extension.
/path/to/document with_unescaped_space.zip -- Has unescaped
space.
document.zip -- Missing /.
HTH
Jean Jourdain
On Sunday, February 6, 2022 at 10:39:09 AM UTC+1 Kaveh wrote:
> not clear for me what you want to do. can you put a sample of input lines
> and output needed?
>
> On Sat, 5 Feb 2022 at 23:09, ejonesss <[email protected]> wrote:
>
>> i was wondering what is the grep i would need to find all occurrences of
>> a word that begins with
>>
>> ftp://ftp.scene.org/pub/demos/artists/0xf/drunkchessboard.zip
>>
>>
>> for example i want to find all lines who has file of “.zip" and begins
>> with “d"
>>
>> drunkchessboard.zip
>>
>> i got the finding .zip part ok that is how i extracted all the zips from
>> a massive 600000 line list
>>
>> now the tricky part is detecting the “/d” part
>>
>>
>>
>> --
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>>
>
>
> --
> Kaveh Bazargan PhD
> Director
> River Valley Technologies <http://rivervalley.io> ● Twitter
> <https://twitter.com/rivervalley1000> ● LinkedIn
> <https://www.linkedin.com/in/bazargankaveh/> ● ORCID
> <https://orcid.org/0000-0002-1414-9098>
> *Accelerating the Communication of Research*
>
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