That ‘.’ doesn’t match the space character between first and last because that
space character is in the pattern.
([A-Z])([a-z]+.) ([A-Z][a-z]+.)
^
So that ‘.’ would just be matching the last character of the first name.
HTH
— Bruce
_bruce__van_allen__santa_cruz_ca_
On Oct 10, 2023, at 4:20 PM, Tim A <[email protected]> wrote:
([AZ])([az]+.) ([AZ][az]+.)
[a-z]+’ so this will match all the lower case letters in the first name
The ‘.’ just adds one more character, and isn’t needed." - but here would match
the presumed space character between First and Last name
... So why does then successfully match the space character as demanded by the
regular expression? Hasn't it been "used up" by the period?
On Tuesday, October 10, 2023 at 2:41:42 PM UTC-7 Bruce Van Allen wrote:
The ‘+’ is quantifying a character class '[a-z]’.
‘[a-z]+’ (without the quotes) means one or more characters in the range ‘a’ to
‘z’.
The ‘.’ just adds one more character, and isn’t needed.
And Tim is correct that there’s no fourth capture, so the ‘\4' is meaningless.
— Bruce
_bruce__van_allen__santa_cruz_ca_
> On Oct 10, 2023, at 1:09 PM, Tim A <[email protected]> wrote:
>
> Find: ([A-Z])([a-z]+.) ([A-Z][a-z]+.)
> Replace: \1\3\4
> Why the "+."? Isn't the space between first and last name all that is needed?
> And what is \4 mean with only three captures?
>
>
> On Monday, October 9, 2023 at 12:10:04 PM UTC-7 Benjamin Irwin wrote:
> That's cool but I had to move one of the periods inside the ")" as follows.
>
> Find: ([A-Z])([a-z]+.) ([A-Z][a-z]+.)
>
> Replace: \1\3\4
>
> On Monday, October 9, 2023 at 10:46:48 AM UTC-4 Kjetil Rå Hauge wrote:
> Try this:
> - Click Case sensitive and Grep
> - Find: "([A-Z])([a-z]+.) ([A-Z][a-z]+)."
> - Replace: "\1\3\4 "
> ________________________________________
> From: [email protected] <[email protected]> on behalf of Bill
> Walker <[email protected]>
> Sent: 09 October 2023 04:32
> To: BBEdit Talk
> Subject: Change First Name SPACE Last Name to First Initial Last Name
>
> Example: Change John Doe to JDoe
>
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