Hi Andrew,
>> superList = iList.copy(); I used
>> iList itself in this method..
>
>oh yeah, good point.
>
>
>>
>> the former was returning instruction handle -1 and the later +1,
>> with a basic super() being first call.
>
>I don't understand your current problem. Are you saying that the
>InstructionHandle you're returning is not correct? Is off by
>one? what
>do you mean by "was not able to insert"?
when I used superList = iList.copy();
the isntruction handle returned was ih = -1
and when I called iList.insert(ih.next(), newList);
I could not see my instrumented instructions in the bytecode
instruction set.
But, when I used the iList itself for iteration. ih = 1
iList.insert(ih.next(),newList);
I could see my instrumented instructions in desired place.
I was wondering why it is so??
>
>>
>> and was not able to insert with former..so choosed the
>> later..however am not sure of reason for this..could you
>please clarify
>> me, why is this happening..is this due to copy()
>> method???????????????????????
>>
>> public InstructionHandle getIListSuper(InstructionList iList){
>>
>> int invkSpec = 0;
>>
>> InstructionHandle seperator = null;
>>
>> InstructionList superList = iList.copy(); // deep copy
>> [COMMENTED OUT IN CURRENT METHOD]
>>
>> for ( Iterator i = superList.iterator (); i.hasNext (); ) {
>> [ USED iList in place of superList in this statement]
>> seperator = ( InstructionHandle ) i.next ();
>>
>> if(seperator.getInstruction() instanceof NEW )
>> invkSpec++;
>>
>> if(seperator.getInstruction() instanceof INVOKESPECIAL )
>> invkSpec--;
>>
>> if(invkSpec < 0 )
>> break;
>> }
>>
>> if(invkSpec < 0) {
>> return seperator
>> }
>>
>> return null;
>> }
>>
>>
>> Thank you
>> Reddy
>
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